Answer
$\sin(x-\pi)=-\sin(x)$
Work Step by Step
$\sin(x-\pi)$
Expand using subtraction formula for sine on page 545:
$=\sin(x)\cos(\pi)-\cos(x)\sin(\pi)$
Evaluate $\cos(\pi)$ and $\sin(\pi)$:
$=\sin(x)*(-1)-\cos(x)*0$
Simplify:
$=-\sin(x)$
Therefore, $\sin(x-\pi)=-\sin(x)$.
