Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 7 - Section 7.2 - Addition and Subtraction Formulas - 7.2 Exercises - Page 551: 26

Answer

$\cos(x-\frac{\pi}{2})=\sin(x)$

Work Step by Step

$\cos(x-\frac{\pi}{2})$ Expand using subtraction formula for cosine on page 545: $=\cos(x)\cos(\frac{\pi}{2})+\sin(x)\sin(\frac{\pi}{2})$ Evaluate $\cos(\frac{\pi}{2})$ and $\sin(\frac{\pi}{2})$: $=\cos(x)*0+\sin(x)*1$ Simplify: $=\sin(x)$ Therefore, $\cos(x-\frac{\pi}{2})=\sin(x)$.
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