Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.6 - The Law of Cosines - 6.6 Exercises - Page 521: 37

Answer

3.828

Work Step by Step

Step 1. Draw a diagram as shown in the figure, the three sides of the triangle (connecting centers of circles) are 9,10,11. Step 2. Use the Law of Cosines to calculate angle C in radians, $11^2=10^2+9^2-2\times9\times10cosC$ which gives $cosC=\frac{1}{3}$ and $\angle C\approx1.231$ Step 3. Repeat Step 2 for other angles to get $\angle B\approx1.030$ and $\angle A\approx0.881$ Step 4. Use Heron's Formula to calculate the are of the triangle: $s=\frac{11+10+9}{2}=15$, $A=\sqrt {15(15-11)(15-10)(15-9)}\approx42.426$ Step 5. Use the formula $A_f=\frac{r^2\theta}{2}$ to calculate the three fan areas inside each circle and the triangle: $A1=\frac{6^2\times0.881}{2}=15.858$, $A2=\frac{5^2\times1.030}{2}=12.875$, $A3=\frac{4^2\times1.231}{2}=9.848$ Step 6. The area between the circles is given by $A-A1-A2-A3=42.426-15.858-12.875-9.848=3.828$ Note: depends on the accuracy during the calculation, there could be a small difference in the final result.
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