Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.6 - The Law of Cosines - 6.6 Exercises - Page 521: 28

Answer

$\approx1180.8$

Work Step by Step

$\angle A=180-\angle B-\angle C=180-98-25=57^{0}$ $\dfrac {1000}{\sin \angle A}=\dfrac {x}{\sin 98}\Rightarrow x=\dfrac {1000\times \sin 98}{\sin \angle A}=\dfrac {1000\times \sin 98}{\sin 57}\approx 1180.8$
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