Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.6 - The Law of Cosines - 6.6 Exercises - Page 521: 35

Answer

40.77

Work Step by Step

Step 1. Draw a line to divide the area into two triangles as shown in the figure (not to scale). Step 2. For the top triangle, use the Law of cosines to obtain the length $x^2=5^2+6^2-2\times5\times6cos100^{\circ}\approx71.42$ and $x\approx8.45$ Step 3. Use the Heron's Formula for the top triangle to get $s=\frac{5+6+8.45}{2}=9.725$ and the area is given by $A1=\sqrt {9.725(9.725-5)(9.725-6)(9.725-8.45)}\approx14.77$ Step 4. Use the Heron's Formula for the top triangle to get $s=\frac{7+8+8.45}{2}=11.725$ and the area is given by $A2=\sqrt {11.725(11.725-7)(11.725-8)(11.725-8.45)}\approx26.00$ Step 5. The total area is $A1+A2=40.77$
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