Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.6 - The Law of Cosines - 6.6 Exercises - Page 521: 21

Answer

$\approx 1.987$

Work Step by Step

$\angle B=180^{0}-35^{0}-85^{0}=60^{0}$ From the law of sines $\dfrac {x}{\sin 35^0}=\dfrac {3}{\sin \angle B}\Rightarrow \dfrac {x}{\sin 35^0}=\dfrac {3}{\sin 60^0}\Rightarrow x=\dfrac {3\sin 35^0}{\sin 60^0}\approx 1.987$
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