Answer
$ \approx53^0$
Work Step by Step
From the law of sines
$\dfrac {8}{\sin 40}=\dfrac {10}{\sin \theta }\Rightarrow \sin \theta =\dfrac {10\times \sin 40}{8}\approx 0.8\Rightarrow \theta \approx \sin ^{-1}\left( 0.8\right) \approx 53^{0}$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 6 - Section 6.6 - The Law of Cosines - 6.6 Exercises - Page 521: 26
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