Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.6 - The Law of Cosines - 6.6 Exercises - Page 521: 24

Answer

$21.28^0$

Work Step by Step

From the law of cosines $4^{2}=11^{2}+10^{2}-2\times 11\times 10\times \cos \theta \Rightarrow \cos \theta =\dfrac {11^{2}+10^{2}-4^{2}}{2\times 11\times 10}$ $=\dfrac {41}{44}\Rightarrow \theta =\cos ^{-1}\left( \dfrac {41}{44}\right) \approx 21.28^{0}$
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