Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 5 - Section 5.2 - Trigonometric Functions of Real Numbers - 5.2 Exercises - Page 417: 36

Answer

$\sin{t} = -\frac{7}{25}$ $\cos{t} = \frac{24}{25}$ $\require{cancel}\tan{t} = -\frac{7}{24}$

Work Step by Step

RECALL: For the terminal point P(x, y) on a unit circle, $\sin{t} = y, \cos{t} = x, \text{ and } \tan{t} = \frac{y}{x}, x\ne0$ Use the formulas above to obtain: $\sin{t} = -\frac{7}{25}$ $\cos{t} = \frac{24}{25}$ $\require{cancel}\tan{t} = \dfrac{-\frac{7}{25}}{\frac{24}{25}} = -\dfrac{7}{25} \cdot \left(\dfrac{25}{24}\right)=-\dfrac{7}{\cancel{25}} \cdot \left(\dfrac{\cancel{25}}{24}\right)=-\dfrac{7}{24}$
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