Answer
$\sin{t} = \frac{9}{41}$
$\cos{t} = \frac{40}{41}$
$\tan{t} = \dfrac{9}{40}$
Work Step by Step
RECALL:
For the terminal point P(x, y) on a unit circle,
$\sin{t} = y, \cos{t} = x, \text{ and } \tan{t} = \frac{y}{x}, x\ne0$
Use the formulas above to obtain:
$\sin{t} = \frac{9}{41}$
$\cos{t} = \frac{40}{41}$
$\tan{t} = \dfrac{\frac{9}{41}}{\frac{40}{41}} = \dfrac{9}{41} \cdot \left(\dfrac{41}{40}\right)=\dfrac{9}{40}$
