Answer
$\sin{t} = \frac{21}{29}$
$\cos{t} = -\frac{20}{29}$
$\require{cancel}\tan{t} = -\dfrac{21}{20}$
Work Step by Step
RECALL:
For the terminal point P(x, y) on a unit circle,
$\sin{t} = y, \cos{t} = x, \text{ and } \tan{t} = \frac{y}{x}, x\ne0$
Use the formulas above to obtain:
$\sin{t} = \frac{21}{29}$
$\cos{t} = -\frac{20}{29}$
$\require{cancel}\tan{t} = \dfrac{\frac{21}{29}}{-\frac{20}{29}} = \dfrac{21}{29} \cdot \left(-\dfrac{29}{20}\right)=\dfrac{21}{\cancel{29}} \cdot \left(-\dfrac{\cancel{29}}{20}\right)=-\dfrac{21}{20}$
