Answer
$\sin{t} = \frac{\sqrt{3}}{2}$
$\cos{t} = -\frac{1}{2}$
$\tan{t} = -\sqrt3$
Work Step by Step
RECALL:
For the terminal point P(x, y) on a unit circle,
$\sin{t} = y, \cos{t} = x, \text{ and } \tan{t} = \frac{y}{x}, x\ne0$
Use the formulas above to obtain:
$\sin{t} = \frac{\sqrt{3}}{2}$
$\cos{t} = -\frac{1}{2}$
$\tan{t} = \dfrac{\frac{\sqrt3}{2}}{-\frac{1}{2}} = \dfrac{\sqrt3}{2} \cdot \left(-\dfrac{2}{1}\right)=-\sqrt3$
