Answer
$\sin{t} = \frac{2\sqrt{2}}{3}$
$\cos{t} = -\frac{1}{3}$
$\tan{t} = -2\sqrt2$
Work Step by Step
RECALL:
For the terminal point P(x, y) on a unit circle,
$\sin{t} = y, \cos{t} = x, \text{ and } \tan{t} = \frac{y}{x}, x\ne0$
Use the formulas above to obtain:
$\sin{t} = \frac{2\sqrt{2}}{3}$
$\cos{t} = -\frac{1}{3}$
$\tan{t} = \dfrac{\frac{2\sqrt2}{3}}{-\frac{1}{3}} = \dfrac{2\sqrt2}{3} \cdot \left(-\dfrac{3}{1}\right)=-2\sqrt2$
