Answer
$\sin{t} = \frac{2\sqrt5}{5}$
$\cos{t} = \frac{\sqrt5}{5}$
$\require{cancel}\tan{t} = 2$
Work Step by Step
RECALL:
For the terminal point P(x, y) on a unit circle,
$\sin{t} = y, \cos{t} = x, \text{ and } \tan{t} = \frac{y}{x}, x\ne0$
Use the formulas above to obtain:
$\sin{t} = \frac{2\sqrt5}{5}$
$\cos{t} = \frac{\sqrt5}{5}$
$\require{cancel}\tan{t} = \dfrac{\frac{2\sqrt5}{5}}{\frac{\sqrt5}{5}} = \dfrac{2\sqrt5}{5} \cdot \left(\dfrac{5}{\sqrt5}\right)=\dfrac{2\cancel{\sqrt5}}{\cancel{5}} \cdot \left(\dfrac{\cancel{5}}{\cancel{\sqrt5}}\right)=2$
