Answer
$\sin{t} = -\frac{12}{13}$
$\cos{t} = -\frac{5}{13}$
$\require{cancel}\tan{t} = \dfrac{12}{5}$
Work Step by Step
RECALL:
For the terminal point P(x, y) on a unit circle,
$\sin{t} = y, \cos{t} = x, \text{ and } \tan{t} = \frac{y}{x}, x\ne0$
Use the formulas above to obtain:
$\sin{t} = -\frac{12}{13}$
$\cos{t} = -\frac{5}{13}$
$\require{cancel}\tan{t} = \dfrac{-\frac{12}{13}}{-\frac{5}{13}} = -\dfrac{12}{13} \cdot \left(-\dfrac{13}{5}\right)=-\dfrac{12}{\cancel{13}} \cdot \left(-\dfrac{\cancel{13}}{5}\right)=\dfrac{12}{5}$
