Answer
$\sin{t} = -\frac{2\sqrt{6}}{5}$
$\cos{t} = \frac{1}{5}$
$\tan{t} = -2\sqrt6$
Work Step by Step
RECALL:
For the terminal point P(x, y) on a unit circle,
$\sin{t} = y, \cos{t} = x, \text{ and } \tan{t} = \frac{y}{x}, x\ne0$
Use the formulas above to obtain:
$\sin{t} = -\frac{2\sqrt{6}}{5}$
$\cos{t} = \frac{1}{5}$
$\tan{t} = \dfrac{-\frac{2\sqrt6}{5}}{\frac{1}{5}} = \dfrac{-2\sqrt6}{5} \cdot \left(\dfrac{5}{1}\right)=-2\sqrt6$
