Answer
(a) Reference Number: $\pi/3$
(b) Terminal Point: $(1/2, \sqrt 3/2)$
Work Step by Step
1. $-11\pi/3 \lt 0$. Add $2\pi$ to it until the result is less than $2\pi$, and greater than 0.
$$-\frac{11\pi}{3} + 2\pi = -\frac{11\pi}{3} + \frac{6\pi}{3} = -\frac{5\pi}{3}$$ $$-\frac{5\pi}{3} + 2\pi = \frac{\pi}{3}$$
2. $\pi/3$ is in Quadrant I, thus, the Reference Number is $\pi/3$:
$$t^- = \pi/3$$
3. According to the Table 1, the terminal point for $\pi/3$ is $(1/2, \sqrt 3/2)$.
