Answer
(0, -1)
Work Step by Step
The reference number t=$\frac{3\pi}{2}$ determines the terminal point Q(0, 1). The terminal points determined by t have to be (0, 1) or (0, -1). Because of the fact that t=$\frac{3\pi}{2}$ is on the negative y-axis, the terminal point should be (0, -1).
