Answer
( $\frac{-\sqrt 3}{2}, \frac{1}{2}$)
Work Step by Step
You cannot locate $\frac{-7\pi}{6}$ on the unit circle so you have to add 2$\pi$, a full unit circle rotation, to it. You end up with $\frac{5\pi}{6}$, which is coterminal to $\frac{-7\pi}{6}$ and is between 0 and 2$\pi$. Look at the unit circle and trace $\frac{5\pi}{6}$ to it corresponding terminal point.
