Answer
($\frac{\sqrt 3}{2}, \frac{-1}{2}$)
Work Step by Step
If you look at the unit circle, you cannot locate $\frac{-\pi}{6}$. You have to add 2$\pi$, a full rotation of the unit circle, to $\frac{-\pi}{6}$. Thus, you get $\frac{11\pi}{6}$. $\frac{11\pi}{6}$ is considered a coterminal angle because it is located between 0 and 2$\pi$. If you look at $\frac{11\pi}{6}$ on the unit circle its terminal point is at ($\frac{\sqrt 3}{2}, \frac{-1}{2}$).
