Answer
(a) Referencial Number: $\pi/4$
(b) Terminal Point: $(\sqrt 2/2, \sqrt 2/2)$
Work Step by Step
1. $17\pi/4 \gt 2\pi$. Subtract $2\pi$ from it until the result is less than $2\pi$.
$$\frac{17\pi}{4} - 2\pi = \frac{17\pi}{4} -\frac{8\pi}{4} = \frac{9\pi}{4}$$ $$\frac{9\pi}{4} - 2\pi = \frac{\pi}{4}$$
2. $\pi/4$ is in Quadrant I, thus, the Reference Number is $\pi/4$:
$$t^- = \pi/4$$
3. According to the Table 1, the terminal point for $\pi/4$ is $(\sqrt 2/2, \sqrt 2/2)$.
