Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Section 2.7 - Combining Functions - 2.7 Exercises - Page 217: 71

Answer

With $h(x)=\sqrt[3]{x},\quad g(x)=x+4,\ \quad$and $f(x)=x^{9}$, $G(x)=f(g(h(x)))=(f\circ g\circ h)(x)$

Work Step by Step

If we were to calculate by hand, we would find the cube root of the number $\qquad$...$ h(x)=\sqrt[3]{x}$, then add 4 (to the number )$\qquad$ .... $g(x)=x+4$ and then raise to the power 9 $\qquad$ .... $f(x)=x^{9}$ In this way, $G(x)=f(g(h(x)))=f\circ g\circ h(x)$
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