Answer
With $g(x)=x^{2}$, and $f(x)=\displaystyle \frac{x}{x+4}$,
$G(x)=f[g(x)]=f\circ g(x)$
Work Step by Step
If we were to calculate by hand,
we would first calculate the square of the number$\qquad$...$ g(x)=x^{2}$,
then divide that number with (number +4) $\qquad$ .... $f(x)=\displaystyle \frac{x}{x+4}$
In this way, $G(x)=f(g(x))=f\circ g(x)$
