Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Section 2.7 - Combining Functions - 2.7 Exercises - Page 217: 66

Answer

With $g(x)=x+3$, and $f(x)=\displaystyle \frac{1}{x}$, $G(x)=f[g(x)]=f\circ g(x)$

Work Step by Step

If we were to calculate by hand, we would first add 3 to the number$\qquad$...$ g(x)=x+3$, then find its reciprocal $\qquad$ .... $f(x)=\displaystyle \frac{1}{x}$ In this way, $G(x)=f(g(x))=f\circ g(x)$
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