Answer
$f\circ g\circ h=(\sqrt{x}-5)^{4}+1$
Work Step by Step
$f(x)=x^{4}+1$ $,$ $g(x)=x-5$ $,$ $h(x)=\sqrt{x}$
First, find $g\circ h$ by substituting $x$ by $h(x)$ in $g(x)$ and simplifying if possible:
$g\circ h=g(h(x))=\sqrt{x}-5$
Finally, to find $f\circ g\circ h$, substitute $x$ by $\sqrt{x}-5$ in $f(x)$ and again, simplify if possible:
$f\circ g\circ h=f(g(h(x)))=(\sqrt{x}-5)^{4}+1$
