Answer
$1$
Work Step by Step
Based on the table, the $y-$value of $g$ at $x=2$ is $5$. Hence, $g(2)=5.$ The $y-$value of $g$ when $x=5$ is $1$. Hence, $g(5)=1$. The given composition function, $
(g \circ g)(2)
,$ evaluates to
\begin{array}{l}\require{cancel}
g(g(2))
\\\\=
g(5)
\\\\=
1
.\end{array}