Answer
With $h(x)=x^{2},\quad g(x)=x+1,\ \quad$and $f(x)=\displaystyle \frac{1}{x}$,
$F(x)=f(g(h(x)))=(f\circ g\circ h)(x)$
Work Step by Step
If we were to calculate by hand,
we would find the square of the number $\qquad$...$ h(x)=x^{2}$,
then add 1 to (the number )$\qquad$ .... $g(x)=x+1$
and then find the reciprocal $\qquad$ .... $f(x)=\displaystyle \frac{1}{x}$
In this way, $F(x)=f(g(h(x)))=f\circ g\circ h(x)$
