Answer
With $g(x)=x-9$, and $f(x)=x^{5}$,
$F(x)=f[g(x)]=f\circ g(x)$
Work Step by Step
If we were to calculate by hand,
we would first subtract nine from the number$\qquad g(x)=x-9$,
then raise that number to the power of 5.... $f(x)=x^{5}$
In this way, $F(x)=f(g(x))=f\circ g(x)$
