Answer
With $h(x)=\sqrt{x},\quad g(x)=x-1,\ \quad$and $f(x)=\sqrt[3]{x}$,
$F(x)=f(g(h(x)))=(f\circ g\circ h)(x)$
Work Step by Step
If we were to calculate by hand,
we would find the square root of the number $\qquad$...$ h(x)=\sqrt{x}$,
then subtract 1 (from the number )$\qquad$ .... $g(x)=x-1$
and then find the cube root $\qquad$ .... $f(x)=\sqrt[3]{x}$
In this way, $F(x)=f(g(h(x)))=f\circ g\circ h(x)$