Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 11 - Section 11.2 - Ellipses - 11.2 Exercises - Page 797: 35

Answer

$y=\pm \sqrt {20-\dfrac {4}{5}x^{2}}$
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Work Step by Step

$\dfrac {x^{2}}{25}+\dfrac {y^{2}}{20}=1\Rightarrow \dfrac {y^{2}}{20}=1-\dfrac {x^{2}}{25}\Rightarrow y^{2}=20-\dfrac {4}{5}x^{2}\Rightarrow y=\pm \sqrt {20-\dfrac {4}{5}x^{2}}$ Now we can graph this equation using graphing calculator as asked in question
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