Answer
(a)
Vertices: $V(±2,0)$
Foci: $F(±\sqrt 3,0)$
Eccentricity:
$e=\frac{\sqrt 3}{2}$
(b)
Length of the major axis:
$2a=4$
Length of the minor axis:
$2b=2$
(c)
Work Step by Step
$\frac{x^2}{4}+y^2=1$
$\frac{x^2}{2^2}+\frac{y^2}{1^2}=1$
The major axis is horizontal.
Equation of an ellipse when major axis is horizontal (center at the origin):
$\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$
So:
$a=2$
$b=1$
$c^2=a^2-b^2=2^-1^2=4-1=3$
$c=\sqrt 3$
(a)
Vertices: $V(±a,0)=V(±2,0)$
Foci: $F(±c,0)=F(±\sqrt 3,0)$
Eccentricity:
$e=\frac{c}{a}=\frac{\sqrt 3}{2}$
(b)
Length of the major axis:
$2a=4$
Length of the minor axis:
$2b=2$