Answer
(a)
Vertices: $V(±7,0)$
Foci: $F(±2\sqrt 6,0)$
Eccentricity:
$e=\frac{2\sqrt 6}{7}$
(b)
Length of the major axis:
$2a=14$
Length of the minor axis:
$2b=10$
(c)
Work Step by Step
$\frac{x^2}{49}+\frac{y^2}{25}1$
$\frac{x^2}{7^2}+\frac{y^2}{5^2}=1$
The major axis is horizontal.
Equation of an ellipse when major axis is horizontal (center at the origin):
$\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$
So:
$a=7$
$b=5$
$c^2=a^2-b^2=7^2-5^2=49-25=24$
$c=2\sqrt 6$
(a)
Vertices: $V(±a,0)=V(±7,0)$
Foci: $F(±c,0)=F(±2\sqrt 6,0)$
Eccentricity:
$e=\frac{c}{a}=\frac{2\sqrt 6}{7}$
(b)
Length of the major axis:
$2a=14$
Length of the minor axis:
$2b=10$
