Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 11 - Section 11.2 - Ellipses - 11.2 Exercises - Page 797: 11

Answer

(a) Vertices: $(0,±9)$ Foci: $(0,±3\sqrt 5)$ Eccentricity: $e=\frac{\sqrt 5}{3}$ (b) Length of the major axis: $2a=18$ Length of the minor axis: $2b=12$ (c)

Work Step by Step

$\frac{x^2}{36}+\frac{y^2}{81}=1$ $\frac{x^2}{6^2}+\frac{y^2}{9^2}=1$ The major axis is vertical. Equation of an ellipse when major axis is vertical (center at the origin): $\frac{x^2}{b^2}+\frac{y^2}{a^2}=1$ So: $a=9$ $b=6$ $c^2=a^2-b^2=9^2-6^2=81-36=45$ $c=3\sqrt 5$ (a) Vertices: $(0,±a)=(0,±9)$ Foci: $(0,±c)=(0,±3\sqrt 5)$ Eccentricity: $e=\frac{c}{a}=\frac{3\sqrt 5}{9}=\frac{\sqrt 5}{3}$ (b) Length of the major axis: $2a=18$ Length of the minor axis: $2b=12$
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