Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 9 - Analytic Geometry - Section 9.6 Polar Equations of Conics - 9.6 Assess Your Understanding - Page 704: 41

Answer

$r=\frac{12}{1-6sin\theta}$.

Work Step by Step

1. Based on the given direction and position of the directrix, we know the equation has a form $r=\frac{ep}{1-e\ sin\theta}$, 2. With $e=6$ and $p=2$, we have $r=\frac{12}{1-6sin\theta}$.
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