Answer
$(x-3)^2+y^2=9$.
Work Step by Step
$r=6cos\theta$,
$r^2=6r\ cos\theta$,
$x^2+y^2=6x$,
$(x-3)^2+y^2=9$.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 9 - Analytic Geometry - Section 9.6 Polar Equations of Conics - 9.6 Assess Your Understanding - Page 704: 2
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