Answer
$3x^2+4y^2-4x-4=0$,
Ellipse.
Work Step by Step
$r(2-cos\theta)=2$,
$2r-r\ cos\theta=2$,
$2r=2+r\ cos\theta$,
$4r^2=(2+r\ cos\theta)^2$,
$4x^2+4y^2=(2+x)^2$,
$3x^2+4y^2-4x-4=0$,
Ellipse.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 9 - Analytic Geometry - Section 9.6 Polar Equations of Conics - 9.6 Assess Your Understanding - Page 704: 34
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