Answer
$9x^2+5y^2-24y-36=0$,
Ellipse.
Work Step by Step
$r(3-2sin\theta)=6$,
$3r-2r\ sin\theta=6$,
$3r=6+2r\ sin\theta$,
$9r^2=(6+2r\ cos\theta)^2$,
$9x^2+9y^2=(6+2x)^2$,
$9x^2+5y^2-24y-36=0$,
Ellipse.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 9 - Analytic Geometry - Section 9.6 Polar Equations of Conics - 9.6 Assess Your Understanding - Page 704: 33
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