Answer
$16x^2+7y^2+48y-64=0$,
Ellipse.
Work Step by Step
$r=\frac{8}{4+3sin\theta}$,
$4r+3r\ sin\theta=8$,
$4r=8-3r\ sin\theta$,
$16r^2=(8-3r\ sin\theta)^2$,
$16x^2+16y^2=(8-3y)^2$,
$16x^2+7y^2+48y-64=0$,
Ellipse.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 9 - Analytic Geometry - Section 9.6 Polar Equations of Conics - 9.6 Assess Your Understanding - Page 704: 27
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