Answer
$4x^2+3y^2-16y-64=0$,
Ellipse.
Work Step by Step
$r=\frac{8}{2-sin\theta}$,
$2r-r\ sin\theta=8$,
$2r=8-r\ sin\theta$,
$4r^2=(8-r\ sin\theta)^2$,
$4x^2+4y^2=(8-y)^2$,
$4x^2+3y^2-16y-64=0$,
Ellipse.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 9 - Analytic Geometry - Section 9.6 Polar Equations of Conics - 9.6 Assess Your Understanding - Page 704: 31
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
