Answer
$3x^2-y^2+12x+9=0$,
Hyperbola.
Work Step by Step
$r=\frac{9}{3-6cos\theta}$,
$r=\frac{3}{1-2cos\theta}$,
$r-2r\ cos\theta=3$,
$r=3+2r\ cos\theta$,
$r^2=(3+2r\ cos\theta)^2$,
$x^2+y^2=(3+2x)^2$,
$3x^2-y^2+12x+9=0$,
Hyperbola.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 9 - Analytic Geometry - Section 9.6 Polar Equations of Conics - 9.6 Assess Your Understanding - Page 704: 29
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