Answer
$y^2+2x-1=0$, parabola.
Work Step by Step
$r=\frac{1}{1+cos\theta}$,
$r+r\ cos\theta=1$,
$r=1-r\ cos\theta$,
$r^2=(1-r\ cos\theta)^2$,
$x^2+y^2=(1-x)^2$,
$y^2=1-2x$,
$y^2+2x-1=0$, parabola.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 9 - Analytic Geometry - Section 9.6 Polar Equations of Conics - 9.6 Assess Your Understanding - Page 704: 25
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