Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.6 Vectors in Space - 8.6 Assess Your Understanding - Page 646: 76


center $(-1,1,0)$, radius $r=\sqrt 3$

Work Step by Step

$3x^2+3y^2+3z^2+6x-6y=3$, $3(x^2+2x+1)+3(y^2-2y+1)+3z^2=3+3+3$, $3(x+1)^2+3(y-1)^2+3(z)^2=9$, $(x+1)^2+(y-1)^2+(z)^2=3$, Thus center $(-1,1,0)$, radius $r=\sqrt 3$
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