Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.6 Vectors in Space - 8.6 Assess Your Understanding - Page 646: 35



Work Step by Step

Let us consider that vector $v$ is given by: $v=pi+qj+rz$ The magnitude of a vector can be determined using the formula $||v||=\sqrt{p^2+q^2+r^2} ...(1)$ We will use the formula (1) to obtain: $||v||=\sqrt{(1)^2+(-1)^2+(1)^2}\\ =\sqrt{1+1+1}\\ =\sqrt{3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.