Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.6 Vectors in Space - 8.6 Assess Your Understanding - Page 646: 41

Answer

$ \sqrt {105}$

Work Step by Step

Let us consider two vectors $v=pi+qj+rz$ and $w=xi+yj+zk$ The addition of the above vectors can be found by adding the individual components of the vector: $v+w=(p+x)i+(q+y)j+(r+z)k$ We apply similar reasoning to simplify the given expression: Therefore, $||v -w||=|| (3i-5j+2k) -(-2i+3j-2k)|| \\ = ||5i-8j+4k|| \\=\sqrt {5^2+(-8)^2+(4)^2} \\ = \sqrt {105}$ Where we used the fact that the magnitude of any vector (let us say $v$) can be determined using the formula $||v||=\sqrt{p^2+q^2+r^2} $
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