Answer
$\sqrt {5}$
Work Step by Step
Let us consider two vectors $v=pi+qj+rz$ and $w=xi+yj+zk$
The addition of the above vectors can be found by adding the individual components of the vector:
$v+w=(p+x)i+(q+y)j+(r+z)k$
We also know that the magnitude of any vector (let us say $v$) can be determined using the formula
$||v||=\sqrt{p^2+q^2+r^2} $
We apply similar reasoning to simplify the given expression:
Therefore, $||v +w||=|| (3i-5j+2k) +(-2i+3j-2k)|| \\
= ||i-2j|| \\=\sqrt {(1)^2+(-2)^2+(0)^2} \\=\sqrt {1+4} \\
= \sqrt {5}$
