Answer
$\sqrt{22}$
Work Step by Step
Let us consider that vector $v$ is given by:
$v=pi+qj+rz$
The magnitude of a vector can be determined using the formula
$||v||=\sqrt{p^2+q^2+r^2} ...(1)$
We will use the formula (1) to obtain:
$||v||=\sqrt{(-2)^2+(3)^2+(-3)^2}\\
=\sqrt{4+9+9}\\
=\sqrt{22}$