Answer
$b \approx7.66$, $a \approx6.43$, $B =50^\circ$.
Work Step by Step
Given $c=10, A=40^\circ$, we have $b=c\ cosA=10cos40^\circ\approx7.66$, $a=c\ sinA=10sin40^\circ\approx6.43$, $B=90^\circ-A=50^\circ$.
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