Answer
$b \approx7.15$, $c \approx9.33$, $B =50^\circ$.
Work Step by Step
Given $a=6, A=40^\circ$, we have $b=a\ cotA=6cot40^\circ\approx7.15$, $c=a\ cscA=6csc40^\circ\approx9.33$, $B=90^\circ-A=50^\circ$.
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