Answer
$0$
Work Step by Step
Recall the co-function identity:
$ \tan (\theta)=\cot(90^{\circ}-\theta)$
Therefore, $\tan(12^{\circ})-\cot(78^{\circ})
\\=\cot(90^{\circ}-12^{ \circ})-\cot(78^{\circ})
\\=\cot 78^{\circ}-\cot \ 78^{\circ}
\\=0$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 7 - Applications of Trigonometric Functions - Section 7.1 Right Triangle Trigonometry ; Applications - 7.1 Assess Your Understanding - Page 540: 20
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