Answer
$a \approx0.71$, $c \approx4.06$, $B =80^\circ$.
Work Step by Step
Given $b=4, A=10^\circ$, we have $a=b\ tanA=4tan10^\circ\approx0.71$, $c=b\ secA=4sec10^\circ\approx4.06$, $B=90^\circ-A=80^\circ$.
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